完成作业一:3-1-3

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2509165031
2026-04-16 15:54:57 +08:00
parent db73c2d474
commit bc6c115d45
3 changed files with 85 additions and 0 deletions

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import numpy as np
# 定义4×4图像矩阵
img = np.array([
[255, 255, 0, 0],
[255, 255, 0, 0],
[0, 0, 255, 255],
[0, 0, 255, 255]
], dtype=np.uint8)
print("原始图像:")
print(img)
print("-" * 30)
# 1. 统计白色(255)和黑色(0)像素数量
white_count = np.sum(img == 255)
black_count = np.sum(img == 0)
print(f"白色像素(255)数量:{white_count}")
print(f"黑色像素(0)数量:{black_count}")
print("-" * 30)
# 2. 水平翻转并打印
img_flip = np.fliplr(img)
print("水平翻转后图像:")
print(img_flip)
print("-" * 30)
# 3. 逆时针旋转90度转置+上下翻转)
# 方法:先转置,再上下翻转(np.flipud)
img_rot90_ccw = np.flipud(img.T)
print("逆时针旋转90度后图像")
print(img_rot90_ccw)

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import numpy as np
# 假设这是从图像中提取的2个特征图
feature_map1 = np.array([[1, 0, 1], [0, 1, 0], [1, 0, 1]])
feature_map2 = np.array([[1, 1, 1], [1, 0, 0], [1, 0, 0]])
# 1) 全代码:将特征图展平为向量
vector1 = feature_map1.flatten() # 展平
vector2 = feature_map2.flatten() # 展平
print("vector1:", vector1)
print("vector2:", vector2)
print("-" * 40)
# 1. 计算 vector1 和 vector2 的欧几里得距离
euclidean_dist = np.linalg.norm(vector1 - vector2)
print(f"欧几里得距离: {euclidean_dist:.4f}")
# 2. 计算 vector1 和 vector2 的余弦相似度
dot_product = np.dot(vector1, vector2)
norm_a = np.linalg.norm(vector1)
norm_b = np.linalg.norm(vector2)
cos_similarity = dot_product / (norm_a * norm_b)
print(f"余弦相似度: {cos_similarity:.4f}")

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import numpy as np
# 1. 定义原始3×3灰度图像
image = np.array([
[100, 150, 200],
[80, 120, 180],
[60, 90, 140]
], dtype=np.uint8)
print("原图:")
print(image)
print("-" * 20)
# 2. 变暗20每个像素值减20uint8会自动截断负数这里所有值减20后均为正无溢出
image_dark = image - 20
print("变暗20后")
print(image_dark)
print("-" * 20)
# 3. 裁剪左上角2×2区域image[0:2, 0:2]
image_crop = image_dark[0:2, 0:2]
print("裁剪左上角2×2后")
print(image_crop)
print("-" * 20)
# 4. 水平翻转使用np.fliplr()
image_flip = np.fliplr(image_crop)
print("水平翻转后:")
print(image_flip)