44 lines
1.9 KiB
Python
44 lines
1.9 KiB
Python
import requests
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import json
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from bs4 import BeautifulSoup
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# 1. 必须包含检测头
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headers = {
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'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36'
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}
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url = 'https://exam.detr.top/exam-b/movies'
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try:
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response = requests.get(url, headers=headers)
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response.encoding = 'utf-8'
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# 2. 保存原始网页源码
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with open('movies.html', 'w', encoding='utf-8') as f_html:
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f_html.write(response.text)
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# 3. 解析数据 (这里假设网页是表格或列表,需要手动调试定位)
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soup = BeautifulSoup(response.text, 'lxml')
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# 示例:假设电影信息在一个 class 为 'movie-item' 的 div 中,实际需要你按 F12 查看源码修改
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# movie_items = soup.select('.movie-item')
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# 获取前10条(或全部)
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# movies_list = []
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# for i, item in enumerate(movie_items[:10]):
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# # 根据实际标签提取:id, title, director, year, rating, duration, genre, actors_count
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# pass
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# ⚠️ 由于无法访问在线真实网页,此处提供解析后构造的示例数据(仅供保存json逻辑参考)
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# 你实际做的时候,需要将上面的 `movies_list` 替换为真实的爬取结果。
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movies_list = [
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{"id": "1", "title": "示例电影A", "director": "导演A", "year": 2022, "rating": 8.5, "duration": 120, "genre": "动作", "actors_count": 4},
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{"id": "2", "title": "示例电影B", "director": "导演B", "year": 2019, "rating": 6.0, "duration": 95, "genre": "喜剧", "actors_count": 6}
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] # 这里要保证爬够10条
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# 4. 保存为 movies.json
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with open('movies.json', 'w', encoding='utf-8') as f_json:
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json.dump(movies_list, f_json, ensure_ascii=False, indent=4)
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print("爬取完成,已保存 movies.json 和 movies.html")
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except Exception as e:
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print(f"爬取失败: {e}") |