9 lines
290 B
Python
9 lines
290 B
Python
import requests
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url = 'https://example.com'
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params = {'key': 'value'}
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response = requests.get(url, params=params)
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if response.status_code == 200:
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htm1_content = response.text
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print("请求成功,获取到HTML内容")
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else:
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print(f"请求失败,状态码:{response.status_code}") |